-35x-40+5x^2=0

Solution for -35x-40+5x^2=0 equation:

-35x-40+5x^2=0

a = 5; b = -35; c = -40;
Δ = b2-4ac
Δ = -352-4·5·(-40)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-45}{2*5}=\frac{-10}{10}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+45}{2*5}=\frac{80}{10}
=8
$